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Guarded Methods in OCaml (2025)
msdz
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> Moreover, it breaks the systematic approach of sending messages to an instance (often presented as one of the key arguments in favor of object-oriented programming).
Is this just a matter of “the code will become spaghetti once too many classes/methods/implementations exist”? And, conversely, is a non-static method with a constrained, i.e. somehow different type (or also the approach of moving a method outside of the class proper) not more confusing?
spankalee
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I'm building a new language and just a couple of days ago the concept of guard methods came up as I was trying to tighten up equality semantics to be more like Swift.
Things like Array.contains() only work if the element type implements the Equatable interface, so it would be a guard method. Maybe something like:
class Array<T> {
contains(value: T): boolean where T extends Equatable { ... }
}
Or possibly a constraint on the `this` type, TypeScript style: class Array<T> {
contains(this: Array<T extends Equatable>, value: T): boolean { ... }
}
https://github.com/elematic/zena/blob/8d77f2b36001078f4d5054...
wavemode
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C++ has this feature. When you define a template class, you can use SFINAE (or, in modern C++, concepts) to make it so that certain methods only exist if the template parameter meets certain requirements.
(Though even this is often unnecessary - for something like your `flatten` example, you could just go ahead and define it unrestricted. Methods of template classes are typechecked lazily - in other words, they don't need to successfully typecheck unless they're called. For this specific use case, SFINAE/concepts would just make the error message nicer.)
Rust also has this feature, with conditional impls.
kibwen
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Rust's approach seems more similar to the approach described in the section on extension methods, which the author admits solves the problem but doesn't like the implications for encapsulation (which isn't a problem in Rust, as long as you're writing this method in the same crate as the type definition). But Rust also doesn't have classic Java-style classes, so the requirement to "keep the member definition within the class" is already meaningless in Rust terms.
tialaramex
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In contrast C++ won't even let you have std::unordered_map<Goose,int> because it wants to know how to compare and hash the keys before making the type at all.